PyQt: How to pass arguments while emitting a signal

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http://www.saltycrane.com/blog/2008/01/pyqt-how-to-pass-arguments-while/

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I often forget how to do this so I'm documenting it here for future reference. If I want to emit a signal and also pass an argument with that signal, I can use the form self.emit(SIGNAL("mySignalName"), myarg). I connect the signal to a method in the usual way. To use the argument, I merely need to specify the argument in the method definition. What often confuses me is that I don't need to specify arguments in the connect statement. The example below emits a signal didSomething and passes two arguments, "important" and "information" to the update_label method.

import sys
import time
from PyQt4.QtCore import * 
from PyQt4.QtGui import * 

#################################################################### 
class MyWindow(QWidget): 
    def __init__(self, *args): 
        QWidget.__init__(self, *args)

        self.label = QLabel(" ")
        layout = QVBoxLayout()
        layout.addWidget(self.label)
        self.setLayout(layout)
        self.connect(self, SIGNAL("didSomething"),
                     self.update_label)
        self.do_something()

    def do_something(self):
        self.emit(SIGNAL("didSomething"), "important", "information")

    def update_label(self, value1, value2):
        self.label.setText(value1 + " " + value2)

####################################################################
if __name__ == "__main__": 
    app = QApplication(sys.argv) 
    w = MyWindow() 
    w.show() 
    sys.exit(app.exec_())